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A full-screen app on your home screen with push notifications, badges and more.

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Setting a notification after a preset time (open door)

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Posted

I want to set up a pushover notification if I leave my garage door open for 2 minutes.  Sometimes the door sticks and I don't want my cats in the garage. 

I'm using my ELK door sensor. I have "If ELK Garage door sensor is violated," but I am stuck there.  How do I write a program to run "If ELK garage door sensor is violated for 2 minutes...." 

I have the notifications all set as well. 

If
     ELK Garage door sensor is violated
Then
      Wait 2 minutes
     You're a pushover
Else
     -------

If the status changes the timer ether starts over or runs else and cancels the timer process in Then.

Edited by larryllix

  • Author

Worked out correctly. I was thinking this was the way, but I didn't try it. 

The way it's written kind of says I will get an alert 2 minutes later every time the door opens.  

2 hours ago, jason.russo.96 said:

Worked out correctly. I was thinking this was the way, but I didn't try it. 

The way it's written kind of says I will get an alert 2 minutes later every time the door opens.  

Unless the door closes before

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Configure browser push notifications

Chrome (Android)
  1. Tap the lock icon next to the address bar.
  2. Tap Permissions → Notifications.
  3. Adjust your preference.
Chrome (Desktop)
  1. Click the padlock icon in the address bar.
  2. Select Site settings.
  3. Find Notifications and adjust your preference.